What is the general solution for 0=-9*sin(2x) ?

The general solution for 0=-9*sin(2x) is x=pin,x= pi/2+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=-9*sin(2x)

0 = - 9 \cdot sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = - 9 sin (2 x)

Switch sides

- 9 sin (2 x) = 0

Divide both sides by

- 9

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

sec^{2} (x) = 4 tan^{2} (x)

5 sin (x) = - 4

- π sin (π x) = 0

7 tan (4 x + 199) = 8 sin (4 x + 199)

4 sin^{2} (x) + 4 cos (x) - 5 = 0, 0 \leq x \leq 2 π

What is the general solution for 0=-9*sin(2x) ?
The general solution for 0=-9*sin(2x) is x=pin,x= pi/2+pin