What is the general solution for -2cos(θ)-sqrt(3)=0 ?

The general solution for -2cos(θ)-sqrt(3)=0 is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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-2cos(θ)-sqrt(3)=0

- 2 cos (θ) - 3 = 0

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

- 2 cos (θ) - 3 = 0

Move

3

to the right side

- 2 cos (θ) = 3

Divide both sides by

- 2

cos (θ) = - \frac{3}{2}

General solutions for

cos (θ) = - \frac{3}{2}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

4 cos^{2} (2 x) = 1

sec (x) = - 4.5973

2 cos (9 x) = 2 - 2 cos (9 x)

sin (2 x) = 32, - π \leq x \leq π

5 cos^{2} (x) - 2 = 0

What is the general solution for -2cos(θ)-sqrt(3)=0 ?
The general solution for -2cos(θ)-sqrt(3)=0 is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin