What is the general solution for 2cos^2(t)-3cos(t)=-1 ?

The general solution for 2cos^2(t)-3cos(t)=-1 is t=2pin,t= pi/3+2pin,t=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(t)-3cos(t)=-1

2 cos^{2} (t) - 3 cos (t) = - 1

t = 2 πn, t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

Solution steps

2 cos^{2} (t) - 3 cos (t) = - 1

Solve by substitution

cos (t) = 1, cos (t) = \frac{1}{2}

cos (t) = 1 : t = 2 πn

cos (t) = \frac{1}{2} : t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

Combine all the solutions

t = 2 πn, t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

cos (t) - cos (2 t) = - 0.75

2 cos (A) = - 3

4 sin (x) cos (x) = cos (x)

cos (x) = 2 sin (x) cos (x)

\frac{cos ( 2 x )}{cos ( x )} = \frac{cos ( x )}{cos ( x )}

What is the general solution for 2cos^2(t)-3cos(t)=-1 ?
The general solution for 2cos^2(t)-3cos(t)=-1 is t=2pin,t= pi/3+2pin,t=(5pi)/3+2pin