What is the general solution for 1=4cos^2(x)-4cos(x)+2 ?

The general solution for 1=4cos^2(x)-4cos(x)+2 is x= pi/3+2pin,x=(5pi)/3+2pin

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1=4cos^2(x)-4cos(x)+2

1 = 4 cos^{2} (x) - 4 cos (x) + 2

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

1 = 4 cos^{2} (x) - 4 cos (x) + 2

Switch sides

4 cos^{2} (x) - 4 cos (x) + 2 = 1

Solve by substitution

cos (x) = \frac{1}{2}

cos (x) = \frac{1}{2} : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

1 = cos (3 θ)

3 sin (2 x) + cos (x) = 0

sinh (a x) = 0

8 sin^{4} (x) - 3 sin^{2} (x) + \frac{1}{4} = 0

- 2 cot (θ) = - 1 - cot^{2} (θ)

What is the general solution for 1=4cos^2(x)-4cos(x)+2 ?
The general solution for 1=4cos^2(x)-4cos(x)+2 is x= pi/3+2pin,x=(5pi)/3+2pin