What is the general solution for 0=2+2sin(θ) ?

The general solution for 0=2+2sin(θ) is θ=(3pi)/2+2pin

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0=2+2sin(θ)

0 = 2 + 2 sin (θ)

θ = \frac{3 π}{2} + 2 πn

Solution steps

0 = 2 + 2 sin (θ)

Switch sides

2 + 2 sin (θ) = 0

Move

2

to the right side

2 sin (θ) = - 2

Divide both sides by

2

sin (θ) = - 1

General solutions for

sin (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

x, 2 cos (x) + 3 = 0

4 cos (x) - 5 = - 8

sin (x) + 4 csc (x) + 5 = 0, 0 \leq x \leq 2 π

r = a sin (3 x)

sin (x) = \frac{18}{25}

What is the general solution for 0=2+2sin(θ) ?
The general solution for 0=2+2sin(θ) is θ=(3pi)/2+2pin