What is the general solution for 11sin(B)+13=4sin(B)+8 ?

The general solution for 11sin(B)+13=4sin(B)+8 is B=-0.79560…+2pin,B=pi+0.79560…+2pin

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11sin(B)+13=4sin(B)+8

11 sin (B) + 13 = 4 sin (B) + 8

B = - 0.79560 \dots + 2 πn, B = π + 0.79560 \dots + 2 πn

Solution steps

11 sin (B) + 13 = 4 sin (B) + 8

Solve by substitution

sin (B) = - \frac{5}{7}

sin (B) = - \frac{5}{7} : B = arcsin (- \frac{5}{7}) + 2 πn, B = π + arcsin (\frac{5}{7}) + 2 πn

Combine all the solutions

B = arcsin (- \frac{5}{7}) + 2 πn, B = π + arcsin (\frac{5}{7}) + 2 πn

Show solutions in decimal form

B = - 0.79560 \dots + 2 πn, B = π + 0.79560 \dots + 2 πn

2 = 4 cos (x)

sin (2 x + π) = 0

sin (\frac{180}{2} - x) = 0.8

cos (2 x) = \frac{( 7 k - 6 )}{4}

sin^{2} (x) - sin (x) + 1 = 0

What is the general solution for 11sin(B)+13=4sin(B)+8 ?
The general solution for 11sin(B)+13=4sin(B)+8 is B=-0.79560…+2pin,B=pi+0.79560…+2pin