What is the general solution for 2cos(3x)=0 ?

The general solution for 2cos(3x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3

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2cos(3x)=0

2 cos (3 x) = 0

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

2 cos (3 x) = 0

Divide both sides by

2

cos (3 x) = 0

General solutions for

cos (3 x) = 0

3 x = \frac{π}{2} + 2 πn, 3 x = \frac{3 π}{2} + 2 πn

Solve

3 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 x = \frac{3 π}{2} + 2 πn : x = \frac{π}{2} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

16 cos^{2} (θ) - 2 = 0

2 tan^{2} (θ) - 5 tan (θ) + 4 = - 8 tan (θ) + 6

1 + \frac{tan ^{2} ( θ )}{sec ( θ )} = sec (θ)

170 = \frac{16 0 ^{2}}{32} sin (2 θ)

sin (3 x) = 3 sin (x) cos (x)

What is the general solution for 2cos(3x)=0 ?
The general solution for 2cos(3x)=0 is x= pi/6+(2pin)/3 ,x= pi/2+(2pin)/3