What is the general solution for sin(θ)=-1,0<= θ<360 ?

The general solution for sin(θ)=-1,0<= θ<360 is θ=270

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sin(θ)=-1,0<= θ<360

sin (θ) = - 1, 0^{\circ} \leq θ < 36 0^{\circ}

θ = 27 0^{\circ}

Solution steps

sin (θ) = - 1, 0^{\circ} \leq θ < 36 0^{\circ}

General solutions for

sin (θ) = - 1

θ = 27 0^{\circ} + 36 0^{\circ} n

Solutions for the range

0 \leq θ < 36 0^{\circ}

θ = 27 0^{\circ}

3 cos^{2} (x) + sin (x) + 1 = 0

2 sin^{2} (\frac{1}{2} x) + C = 2 cos (\frac{x}{2}) sin (\frac{x}{2}) + C

sin (x) = 7

sin^{2} (x) cos^{2} (x) = \frac{2 - 2}{16}

(sin (x) - 1) (sin (x) - 5) = 0

What is the general solution for sin(θ)=-1,0<= θ<360 ?
The general solution for sin(θ)=-1,0<= θ<360 is θ=270