What is the general solution for 1+sin(pi*t)= 3/2 ?

The general solution for 1+sin(pi*t)= 3/2 is t= 1/6+2n,t= 5/6+2n

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1+sin(pi*t)= 3/2

1 + sin (π \cdot t) = \frac{3}{2}

t = \frac{1}{6} + 2 n, t = \frac{5}{6} + 2 n

Solution steps

1 + sin (π t) = \frac{3}{2}

Move

1

to the right side

sin (π t) = \frac{1}{2}

General solutions for

sin (π t) = \frac{1}{2}

π t = \frac{π}{6} + 2 πn, π t = \frac{5 π}{6} + 2 πn

Solve

π t = \frac{π}{6} + 2 πn : t = \frac{1}{6} + 2 n

Solve

π t = \frac{5 π}{6} + 2 πn : t = \frac{5}{6} + 2 n

t = \frac{1}{6} + 2 n, t = \frac{5}{6} + 2 n

- cos (x) = sin^{2} (x) - 1

csc (x) = \frac{5}{2}

csc (x) = \frac{5}{4}

3 cos (2 θ) = 9 cos (θ) - 6

4 sin (\frac{x}{3}) - 3 = 0

What is the general solution for 1+sin(pi*t)= 3/2 ?
The general solution for 1+sin(pi*t)= 3/2 is t= 1/6+2n,t= 5/6+2n