What is the general solution for sin(θ)=-4/5 ,(7pi)/2 <= θ<4pi,cos(2θ) ?

The general solution for sin(θ)=-4/5 ,(7pi)/2 <= θ<4pi,cos(2θ) is θ=-0.92729…+4pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=-4/5 ,(7pi)/2 <= θ<4pi,cos(2θ)

sin (θ) = - \frac{4}{5}, \frac{7 π}{2} \leq θ < 4 π, cos (2 θ)

θ = - 0.92729 \dots + 4 π

Degrees

θ = 666.86989 \dots^{\circ}

Solution steps

sin (θ) = - \frac{4}{5}, \frac{7 π}{2} \leq θ < 4 π, cos (2 θ)

Apply trig inverse properties

sin (θ) = - \frac{4}{5}

General solutions for

sin (θ) = - \frac{4}{5}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

θ = arcsin (- \frac{4}{5}) + 2 πn, θ = π + arcsin (\frac{4}{5}) + 2 πn

θ = arcsin (- \frac{4}{5}) + 2 πn, θ = π + arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

\frac{7 π}{2} \leq θ < 4 π

θ = - arcsin (\frac{4}{5}) + 4 π

Show solutions in decimal form

θ = - 0.92729 \dots + 4 π

cos (2 x) - 2 sin^{2} (x) - sin (x) = 1

- 8 sin (θ) = - 3

sin (x) + 1 = 1

- 12 cot (x) - 43 = 0

3 sin^{2} (t) = 2 cos (t) sin (t)

What is the general solution for sin(θ)=-4/5 ,(7pi)/2 <= θ<4pi,cos(2θ) ?
The general solution for sin(θ)=-4/5 ,(7pi)/2 <= θ<4pi,cos(2θ) is θ=-0.92729…+4pi