What is the general solution for 1sin(30)=1.7sin(θ) ?

The general solution for 1sin(30)=1.7sin(θ) is θ=0.29853…+360n,θ=180-0.29853…+360n

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1sin(30)=1.7sin(θ)

1 sin (3 0^{\circ}) = 1.7 sin (θ)

θ = 0.29853 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.29853 \dots + 36 0^{\circ} n

Solution steps

1 \cdot sin (3 0^{\circ}) = 1.7 sin (θ)

sin (3 0^{\circ}) = \frac{1}{2}

1 \cdot \frac{1}{2} = 1.7 sin (θ)

Switch sides

1.7 sin (θ) = 1 \cdot \frac{1}{2}

Multiply both sides by

10

17 sin (θ) = 5

Divide both sides by

17

sin (θ) = \frac{5}{17}

Apply trig inverse properties

θ = arcsin (\frac{5}{17}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{5}{17}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.29853 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.29853 \dots + 36 0^{\circ} n

sin (x) = \pm \frac{1}{2}

30 = 211.49 - 20.96 cosh (0.03291765 x)

tan (θ) = \frac{2}{- 3}

x, z = arcsin (\frac{x y}{x ^{2} + y ^{2}})

\frac{tan ( x ) + cos ( x )}{( 1 + sin ( x ) )} = \frac{1}{cos ( x )}

What is the general solution for 1sin(30)=1.7sin(θ) ?
The general solution for 1sin(30)=1.7sin(θ) is θ=0.29853…+360n,θ=180-0.29853…+360n