What is the general solution for sin^2(θ)=2sin(θ) ?

The general solution for sin^2(θ)=2sin(θ) is θ=2pin,θ=pi+2pin

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sin^2(θ)=2sin(θ)

sin^{2} (θ) = 2 sin (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

sin^{2} (θ) = 2 sin (θ)

Solve by substitution

sin (θ) = 2, sin (θ) = 0

sin (θ) = 2 :

No Solution

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

1 - sin (2 x) = 0

cos (p) - sin (p) = 1

x, y = 2 sin (x)

2 cos (3 x) + cos (2 x) + 1 = 0

4 + 2 tan^{2} (θ) = 5 tan^{2} (θ) + 3

What is the general solution for sin^2(θ)=2sin(θ) ?
The general solution for sin^2(θ)=2sin(θ) is θ=2pin,θ=pi+2pin