What is the general solution for 0=2(1+cos(θ)) ?

The general solution for 0=2(1+cos(θ)) is θ=pi+2pin

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0=2(1+cos(θ))

0 = 2 (1 + cos (θ))

θ = π + 2 πn

Solution steps

0 = 2 (1 + cos (θ))

Switch sides

2 (1 + cos (θ)) = 0

Divide both sides by

2

1 + cos (θ) = 0

Move

1

to the right side

cos (θ) = - 1

General solutions for

cos (θ) = - 1

θ = π + 2 πn

\frac{csc ( x )}{5} - 2 = 0

sin (4 y) + sin (6 y) + cos (y) = 0, 0 \leq y \leq \frac{π}{2}

2 \cdot cos^{2} (x) - sin^{2} (x) = 0

cos (θ) = - \frac{35}{6}

5 cos (x) + 2 sin (x) = 0

What is the general solution for 0=2(1+cos(θ)) ?
The general solution for 0=2(1+cos(θ)) is θ=pi+2pin