What is the general solution for 2+4cos(θ)=0 ?

The general solution for 2+4cos(θ)=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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2+4cos(θ)=0

2 + 4 cos (θ) = 0

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

2 + 4 cos (θ) = 0

Move

2

to the right side

4 cos (θ) = - 2

Divide both sides by

4

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

- cos (x) - 4 sin^{2} (x) + 2 = 0

2 sin (t) + cos (2 t) = 0

2 cos^{2} (x) - 1 + cos (x) = 2

23 = csc (x) cot (x)

4 sin^{2} (x) - 4 sin (x) = - 1

What is the general solution for 2+4cos(θ)=0 ?
The general solution for 2+4cos(θ)=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin