What is the general solution for sin^2(x)-2=sin(x) ?

The general solution for sin^2(x)-2=sin(x) is x=(3pi)/2+2pin

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sin^2(x)-2=sin(x)

sin^{2} (x) - 2 = sin (x)

x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - 2 = sin (x)

Solve by substitution

sin (x) = 2, sin (x) = - 1

sin (x) = 2 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

arccosh (x) = \frac{2 π}{7}

arccosh (x) = \frac{2 π}{5}

- 6 sin (x) - 4 sin (2 x) = 0

t, x = 2 cos (t)

6 sin (θ) = 2.5 cos (θ)

What is the general solution for sin^2(x)-2=sin(x) ?
The general solution for sin^2(x)-2=sin(x) is x=(3pi)/2+2pin