What is the general solution for -2sin(2y)=0 ?

The general solution for -2sin(2y)=0 is y=pin,y= pi/2+pin

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-2sin(2y)=0

- 2 sin (2 y) = 0

y = πn, y = \frac{π}{2} + πn

Solution steps

- 2 sin (2 y) = 0

Divide both sides by

- 2

sin (2 y) = 0

General solutions for

sin (2 y) = 0

2 y = 0 + 2 πn, 2 y = π + 2 πn

Solve

2 y = 0 + 2 πn : y = πn

Solve

2 y = π + 2 πn : y = \frac{π}{2} + πn

y = πn, y = \frac{π}{2} + πn

- 3 + 4 (cos^{2} (x))^{2} + 3 sin^{2} (x) = 0

4 sin (x - 3 0^{\circ}) - 1.3 = 0

2 cos (\frac{θ}{2}) = cos (θ) + 1

cos (3 x) + sin (3 x) = 0

\frac{1}{3} = tan (x)

What is the general solution for -2sin(2y)=0 ?
The general solution for -2sin(2y)=0 is y=pin,y= pi/2+pin