What is the general solution for tan(3x+pi/2)=-1 ?

The general solution for tan(3x+pi/2)=-1 is x=(pin)/3+pi/(12)

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tan(3x+pi/2)=-1

tan (3 x + \frac{π}{2}) = - 1

x = \frac{πn}{3} + \frac{π}{12}

Solution steps

tan (3 x + \frac{π}{2}) = - 1

General solutions for

tan (3 x + \frac{π}{2}) = - 1

3 x + \frac{π}{2} = \frac{3 π}{4} + πn

Solve

3 x + \frac{π}{2} = \frac{3 π}{4} + πn : x = \frac{πn}{3} + \frac{π}{12}

x = \frac{πn}{3} + \frac{π}{12}

15 = 60 sin (\frac{π}{15 [ 0 - d ]}) + 75

cos (θ) = \frac{2 5}{58}

tan (θ) = \frac{m ^{2} - m ^{1}}{1 + m ^{2} \cdot m ^{1}}, m^{2}

0 = - 1 - tan^{2} (θ) + 2 tan (θ)

u, x = tanh (u)

What is the general solution for tan(3x+pi/2)=-1 ?
The general solution for tan(3x+pi/2)=-1 is x=(pin)/3+pi/(12)