What is the general solution for 0=-1-tan^2(θ)+2tan(θ) ?

The general solution for 0=-1-tan^2(θ)+2tan(θ) is θ= pi/4+pin

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0=-1-tan^2(θ)+2tan(θ)

0 = - 1 - tan^{2} (θ) + 2 tan (θ)

θ = \frac{π}{4} + πn

Solution steps

0 = - 1 - tan^{2} (θ) + 2 tan (θ)

Switch sides

- 1 - tan^{2} (θ) + 2 tan (θ) = 0

Solve by substitution

tan (θ) = 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn

u, x = tanh (u)

3 + 2 cos (x) = 0

2 cos^{2} (θ) - 7 cos (θ) = - 3

tan^{2} (x) = 3 - 2 tan (x)

tan (3 x) + tan (5 x) = 0

What is the general solution for 0=-1-tan^2(θ)+2tan(θ) ?
The general solution for 0=-1-tan^2(θ)+2tan(θ) is θ= pi/4+pin