What is the general solution for -3sin(B)-2=sin(B)-2 ?

The general solution for -3sin(B)-2=sin(B)-2 is B=2pin,B=pi+2pin

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-3sin(B)-2=sin(B)-2

- 3 sin (B) - 2 = sin (B) - 2

B = 2 πn, B = π + 2 πn

Solution steps

- 3 sin (B) - 2 = sin (B) - 2

Solve by substitution

sin (B) = 0

sin (B) = 0 : B = 2 πn, B = π + 2 πn

Combine all the solutions

B = 2 πn, B = π + 2 πn

sin (\frac{θ}{2}) = 2 - sin (\frac{θ}{2})

2 sin (x) cos (x) = cos (2 x)

(tan (x) + 1) (2 sin (x) - 1) = 0

sin (θ) = \frac{0.3924}{cos ( θ )}

x, y = 3 sin (x)

What is the general solution for -3sin(B)-2=sin(B)-2 ?
The general solution for -3sin(B)-2=sin(B)-2 is B=2pin,B=pi+2pin