What is the general solution for (1-sin(θ))/(3+3sin(θ))=1 ?

The general solution for (1-sin(θ))/(3+3sin(θ))=1 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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(1-sin(θ))/(3+3sin(θ))=1

\frac{1 - sin ( θ )}{3 + 3 sin ( θ )} = 1

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

\frac{1 - sin ( θ )}{3 + 3 sin ( θ )} = 1

Solve by substitution

sin (θ) = - \frac{1}{2}

sin (θ) = - \frac{1}{2} : θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Combine all the solutions

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

cos (θ) = \frac{12}{15}

arctan (x) = 45

tan^{2} (x) + cot^{2} (x) - 2 = 0

12 sin (C) + 6 = 5 sin (C) + 6

10 sin (t) cos (t) = - 6 sin (t)

What is the general solution for (1-sin(θ))/(3+3sin(θ))=1 ?
The general solution for (1-sin(θ))/(3+3sin(θ))=1 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin