What is the general solution for (sin(x)-4)(sin(x)-1)=0 ?

The general solution for (sin(x)-4)(sin(x)-1)=0 is x= pi/2+2pin

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(sin(x)-4)(sin(x)-1)=0

(sin (x) - 4) (sin (x) - 1) = 0

x = \frac{π}{2} + 2 πn

Solution steps

(sin (x) - 4) (sin (x) - 1) = 0

Solving each part separately

sin (x) - 4 = 0 or sin (x) - 1 = 0

sin (x) - 4 = 0 :

No Solution

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn

tan (2 x) = 0.6

2 sin (3 θ) = - 1

2 + 2 cos (θ) = 2 - 2 cos (θ)

1 + 4 sin (x) = 0

cos^{2} (x) = \frac{3}{2} sin (x)

What is the general solution for (sin(x)-4)(sin(x)-1)=0 ?
The general solution for (sin(x)-4)(sin(x)-1)=0 is x= pi/2+2pin