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Popular >

2sin^2(t)+3sin(t)+1=0

Solution

2 sin^{2} (t) + 3 sin (t) + 1 = 0

Solution

t = \frac{7 π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn, t = \frac{3 π}{2} + 2 πn

+1

Solution steps

2 sin^{2} (t) + 3 sin (t) + 1 = 0

Solve by substitution

sin (t) = - \frac{1}{2}, sin (t) = - 1

sin (t) = - \frac{1}{2} : t = \frac{7 π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn

sin (t) = - 1 : t = \frac{3 π}{2} + 2 πn

Combine all the solutions

t = \frac{7 π}{6} + 2 πn, t = \frac{11 π}{6} + 2 πn, t = \frac{3 π}{2} + 2 πn

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Frequently Asked Questions (FAQ)

What is the general solution for 2sin^2(t)+3sin(t)+1=0 ?
The general solution for 2sin^2(t)+3sin(t)+1=0 is t=(7pi)/6+2pin,t=(11pi)/6+2pin,t=(3pi)/2+2pin