What is the general solution for cos(x)= 1/2 ,0<= x<2pi ?

The general solution for cos(x)= 1/2 ,0<= x<2pi is x= pi/3 ,x=(5pi)/3

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cos(x)= 1/2 ,0<= x<2pi

cos (x) = \frac{1}{2}, 0 \leq x < 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

Solution steps

cos (x) = \frac{1}{2}, 0 \leq x < 2 π

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

sin (b) = \frac{12}{13}

3 = 1 + sec (x)

3 sin^{2} (x) - 7 sin (x) = 6

2 sin (x) (cos (x) - sin (x)) + (cos (x) - sin (x)) = 0

2 cos^{2} (x) - sin^{2} (x) + 1 = 0

What is the general solution for cos(x)= 1/2 ,0<= x<2pi ?
The general solution for cos(x)= 1/2 ,0<= x<2pi is x= pi/3 ,x=(5pi)/3