What is the general solution for 4-3sin(θ)=7 ?

The general solution for 4-3sin(θ)=7 is θ=(3pi)/2+2pin

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4-3sin(θ)=7

4 - 3 sin (θ) = 7

θ = \frac{3 π}{2} + 2 πn

Solution steps

4 - 3 sin (θ) = 7

Move

4

to the right side

- 3 sin (θ) = 3

Divide both sides by

- 3

sin (θ) = - 1

General solutions for

sin (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

sin (x) cos (x) = - \frac{1}{4}, 0 \leq x \leq 2 π

tan (x) = (\frac{4}{3})

cos (2 x) - sin^{2} (x) - 1 = 0

x, sin (x) - cos (x) = 0

4 sin^{2} (x) + 4 cos (2 x) = 1

What is the general solution for 4-3sin(θ)=7 ?
The general solution for 4-3sin(θ)=7 is θ=(3pi)/2+2pin