What is the general solution for 100+60sin((7pi)/3 x)=100,0<= x<= 1 ?

The general solution for 100+60sin((7pi)/3 x)=100,0<= x<= 1 is x=0,x= 3/7 ,x= 6/7

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100+60sin((7pi)/3 x)=100,0<= x<= 1

100 + 60 sin (\frac{7 π}{3} x) = 100, 0 \leq x \leq 1

x = 0, x = \frac{3}{7}, x = \frac{6}{7}

Solution steps

100 + 60 sin (\frac{7 π}{3} x) = 100, 0 \leq x \leq 1

Subtract

100

from both sides

100 + 60 sin (\frac{7 π}{3} x) - 100 = 100 - 100

Simplify

60 sin (\frac{7 π}{3} x) = 0

Divide both sides by

60

sin (\frac{7 π}{3} x) = 0

General solutions for

sin (\frac{7 π}{3} x) = 0

\frac{7 π}{3} x = 0 + 2 πn, \frac{7 π}{3} x = π + 2 πn

Solve

\frac{7 π}{3} x = 0 + 2 πn : x = \frac{6 n}{7}

Solve

\frac{7 π}{3} x = π + 2 πn : x = \frac{3}{7} + \frac{6 n}{7}

x = \frac{6 n}{7}, x = \frac{3}{7} + \frac{6 n}{7}

Solutions for the range

0 \leq x \leq 1

x = 0, x = \frac{3}{7}, x = \frac{6}{7}

cot (θ) = 4, cos (θ) < 0

(tan (x) + 1) (sin (x) - 1) = 0

5 cos (a) + 8 = 3 cos (a) + 6

cos (x) = \frac{- 3}{4}

3 cot^{2} (x) - 9 = 0

What is the general solution for 100+60sin((7pi)/3 x)=100,0<= x<= 1 ?
The general solution for 100+60sin((7pi)/3 x)=100,0<= x<= 1 is x=0,x= 3/7 ,x= 6/7