What is the general solution for 2*cos(x)-1=0 ?

The general solution for 2*cos(x)-1=0 is x= pi/3+2pin,x=(5pi)/3+2pin

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2*cos(x)-1=0

2 \cdot cos (x) - 1 = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

2 cos (x) - 1 = 0

Move

1

to the right side

2 cos (x) = 1

Divide both sides by

2

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

cos (x) + 3 sin (x) = 2

2 sin (θ) = - 2, 0 \leq θ < 2 π

y, x = arcsin (y^{2})

cos^{2} (2 x) + cos (2 x) - \frac{3}{4} = 0

sin^{2} (\frac{x}{2}) = a

What is the general solution for 2*cos(x)-1=0 ?
The general solution for 2*cos(x)-1=0 is x= pi/3+2pin,x=(5pi)/3+2pin