What is the general solution for cos(x)=-0.3178,0<= x<= 2pi ?

The general solution for cos(x)=-0.3178,0<= x<= 2pi is x=1.89420…,x=4.38898…

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cos(x)=-0.3178,0<= x<= 2pi

cos (x) = - 0.3178, 0 \leq x \leq 2 π

x = 1.89420 \dots, x = 4.38898 \dots

Solution steps

cos (x) = - 0.3178, 0 \leq x \leq 2 π

Apply trig inverse properties

x = arccos (- 0.3178) + 2 πn, x = - arccos (- 0.3178) + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = 1.89420 \dots, x = 4.38898 \dots

arccos (x) = \frac{π}{3}

arccos (x) = \frac{π}{2}

2 cos (2 θ) = 1

a^{2} cos (θ) sin (θ) = 0

6 sec^{2} (9 x) - 5 = 7

What is the general solution for cos(x)=-0.3178,0<= x<= 2pi ?
The general solution for cos(x)=-0.3178,0<= x<= 2pi is x=1.89420…,x=4.38898…