What is the general solution for -4sin(x)=-cos^2(x)+5 ?

The general solution for -4sin(x)=-cos^2(x)+5 is No Solution for x\in\mathbb{R}

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-4sin(x)=-cos^2(x)+5

- 4 sin (x) = - cos^{2} (x) + 5

No Solution for x \in R

Solution steps

- 4 sin (x) = - cos^{2} (x) + 5

Subtract

- cos^{2} (x) + 5

from both sides

- 4 sin (x) + cos^{2} (x) - 5 = 0

Rewrite using trig identities

- 4 - sin^{2} (x) - 4 sin (x) = 0

Solve by substitution

sin (x) = - 2

sin (x) = - 2 :

No Solution

Combine all the solutions

No Solution for x \in R

cos (x) = sec (x) (1 - cos^{2} (x))

4 cos^{2} (x) - 4 sin (x) - 5 = 0, 0 \leq x \leq 2 π

x, y = cos (b x + y)

\frac{300}{1 - sin ( θ )} = 400 + 400 sin (θ)

sin (t) = \frac{2}{3}

What is the general solution for -4sin(x)=-cos^2(x)+5 ?
The general solution for -4sin(x)=-cos^2(x)+5 is No Solution for x\in\mathbb{R}