What is the general solution for -cos(x)=0.9 ?

The general solution for -cos(x)=0.9 is x=2.69056…+2pin,x=-2.69056…+2pin

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-cos(x)=0.9

- cos (x) = 0.9

x = 2.69056 \dots + 2 πn, x = - 2.69056 \dots + 2 πn

Solution steps

- cos (x) = 0.9

Divide both sides by

- 1

cos (x) = - 0.9

Apply trig inverse properties

x = arccos (- 0.9) + 2 πn, x = - arccos (- 0.9) + 2 πn

Show solutions in decimal form

x = 2.69056 \dots + 2 πn, x = - 2.69056 \dots + 2 πn

3 cos (θ) - 2 sin (θ) cos (θ) = 0

sec (x) + sin^{2} (x) + cos^{2} (x) = tan^{2} (x)

4 sin^{2} (x) - 3 = 4, sin (2 x) - 3 = 0

tan^{2} (θ) + tan (θ) = 6, 0 \leq θ < 18 0^{\circ}

sin (2 x) = 5 sin (x)

What is the general solution for -cos(x)=0.9 ?
The general solution for -cos(x)=0.9 is x=2.69056…+2pin,x=-2.69056…+2pin