What is the general solution for 4cos(θ)=4(1-cos(θ)) ?

The general solution for 4cos(θ)=4(1-cos(θ)) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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4cos(θ)=4(1-cos(θ))

4 cos (θ) = 4 (1 - cos (θ))

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

4 cos (θ) = 4 (1 - cos (θ))

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

2 cos (x) = 1.7

sin (2 x + 30) = 0.8

1 - 2 sin (x) = - 1

4 tan^{2} (x) + sec (x) = - 2 tan^{2} (x) + sec^{2} (x) - 3

sin (α) = 0, 8 y (α) α < 9 0^{\circ}, cos (α)

What is the general solution for 4cos(θ)=4(1-cos(θ)) ?
The general solution for 4cos(θ)=4(1-cos(θ)) is θ= pi/3+2pin,θ=(5pi)/3+2pin