What is the general solution for 2sin^2(x)-3cos(-x)-3=0 ?

The general solution for 2sin^2(x)-3cos(-x)-3=0 is x=pi+2pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin

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2sin^2(x)-3cos(-x)-3=0

2 sin^{2} (x) - 3 cos (- x) - 3 = 0

x = π + 2 πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

2 sin^{2} (x) - 3 cos (- x) - 3 = 0

Rewrite using trig identities

- 1 - 2 cos^{2} (x) - 3 cos (x) = 0

Solve by substitution

cos (x) = - 1, cos (x) = - \frac{1}{2}

cos (x) = - 1 : x = π + 2 πn

cos (x) = - \frac{1}{2} : x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Combine all the solutions

x = π + 2 πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

49.55 cos (θ) - 30 sin (θ) = 1.225

tan (2 x) + sin (2 x) + cos (2 x) = sec (2 x)

tan (x) cos^{2} (x) - tan (x) = 0, (0, 2 π)

cos (A) - 1 = 0

4 sin (x) + 7 = 3

What is the general solution for 2sin^2(x)-3cos(-x)-3=0 ?
The general solution for 2sin^2(x)-3cos(-x)-3=0 is x=pi+2pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin