What is the general solution for solvefor h=7cos(pi/3 t),t ?

The general solution for solvefor h=7cos(pi/3 t),t is t=(3arccos(h/7))/pi+6n,t=-(3arccos(h/7))/pi+6n

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solvefor h=7cos(pi/3 t),t

solve for

h = 7 cos (\frac{π}{3} t), t

t = \frac{3 arccos ( \frac{h}{7} )}{π} + 6 n, t = - \frac{3 arccos ( \frac{h}{7} )}{π} + 6 n

Solution steps

h = 7 cos (\frac{π}{3} t)

Switch sides

7 cos (\frac{π}{3} t) = h

Divide both sides by

7

cos (\frac{π}{3} t) = \frac{h}{7}

Apply trig inverse properties

\frac{π}{3} t = arccos (\frac{h}{7}) + 2 πn, \frac{π}{3} t = - arccos (\frac{h}{7}) + 2 πn

Solve

\frac{π}{3} t = arccos (\frac{h}{7}) + 2 πn : t = \frac{3 arccos ( \frac{h}{7} )}{π} + 6 n

Solve

\frac{π}{3} t = - arccos (\frac{h}{7}) + 2 πn : t = - \frac{3 arccos ( \frac{h}{7} )}{π} + 6 n

t = \frac{3 arccos ( \frac{h}{7} )}{π} + 6 n, t = - \frac{3 arccos ( \frac{h}{7} )}{π} + 6 n

3 + 3 sin (θ) = 3 + 3 cos (θ)

- 3 = tan (θ)

cot (θ) = 13

arctan (0.2 x) + arctan (0.0625 x) = 5 4^{\circ}

sin^{2} (θ) + cos (θ) = 1

What is the general solution for solvefor h=7cos(pi/3 t),t ?
The general solution for solvefor h=7cos(pi/3 t),t is t=(3arccos(h/7))/pi+6n,t=-(3arccos(h/7))/pi+6n