What is the general solution for 3tan(θ)=-3,0<= θ<= 2pi ?

The general solution for 3tan(θ)=-3,0<= θ<= 2pi is θ=(3pi)/4 ,θ=(7pi)/4

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3tan(θ)=-3,0<= θ<= 2pi

3 tan (θ) = - 3, 0 \leq θ \leq 2 π

θ = \frac{3 π}{4}, θ = \frac{7 π}{4}

Solution steps

3 tan (θ) = - 3, 0 \leq θ \leq 2 π

Divide both sides by

3

tan (θ) = - 1

General solutions for

tan (θ) = - 1

θ = \frac{3 π}{4} + πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{3 π}{4}, θ = \frac{7 π}{4}

sin (x) = \frac{39}{62}

2 cot^{2} (x) - csc^{2} (x) + csc (x) = 4

2 \cdot sin (x) + 1 = 3 \cdot cos (x)

\frac{sin ( θ )}{cos ( θ )} = 0

0 = sin (y)

What is the general solution for 3tan(θ)=-3,0<= θ<= 2pi ?
The general solution for 3tan(θ)=-3,0<= θ<= 2pi is θ=(3pi)/4 ,θ=(7pi)/4