What is the general solution for cos(θ)=-8/11 ?

The general solution for cos(θ)=-8/11 is θ=2.38513…+2pin,θ=-2.38513…+2pin

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cos(θ)=-8/11

cos (θ) = - \frac{8}{11}

θ = 2.38513 \dots + 2 πn, θ = - 2.38513 \dots + 2 πn

Solution steps

cos (θ) = - \frac{8}{11}

Apply trig inverse properties

θ = arccos (- \frac{8}{11}) + 2 πn, θ = - arccos (- \frac{8}{11}) + 2 πn

Show solutions in decimal form

θ = 2.38513 \dots + 2 πn, θ = - 2.38513 \dots + 2 πn

sin (θ) = \frac{3}{12}

cos (x) = \frac{12}{17}

x, (d^{3} + d^{2} + 1) y = cos (3 x)

arccos (2 x - 1) = \frac{π}{6}

sin (θ) - cos (\frac{θ}{2}) = 0

What is the general solution for cos(θ)=-8/11 ?
The general solution for cos(θ)=-8/11 is θ=2.38513…+2pin,θ=-2.38513…+2pin