What is the general solution for 2sqrt(3)cos(θ-pi/3)=3,0<= θ<= 2pi ?

The general solution for 2sqrt(3)cos(θ-pi/3)=3,0<= θ<= 2pi is θ= pi/2 ,θ= pi/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sqrt(3)cos(θ-pi/3)=3,0<= θ<= 2pi

23 cos (θ - \frac{π}{3}) = 3, 0 \leq θ \leq 2 π

θ = \frac{π}{2}, θ = \frac{π}{6}

Solution steps

23 cos (θ - \frac{π}{3}) = 3, 0 \leq θ \leq 2 π

Divide both sides by

23

cos (θ - \frac{π}{3}) = \frac{3}{2}

General solutions for

cos (θ - \frac{π}{3}) = \frac{3}{2}

θ - \frac{π}{3} = \frac{π}{6} + 2 πn, θ - \frac{π}{3} = \frac{11 π}{6} + 2 πn

Solve

θ - \frac{π}{3} = \frac{π}{6} + 2 πn : θ = 2 πn + \frac{π}{2}

Solve

θ - \frac{π}{3} = \frac{11 π}{6} + 2 πn : θ = 2 πn + \frac{13 π}{6}

θ = 2 πn + \frac{π}{2}, θ = 2 πn + \frac{13 π}{6}

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{2}, θ = \frac{π}{6}

sin (6 x) = 1

3 sin (θ) = 2 cos (θ)

\frac{2}{2} = sin (x)

tan (θ) = \frac{12}{6}

tan (θ) = \frac{12}{7}

What is the general solution for 2sqrt(3)cos(θ-pi/3)=3,0<= θ<= 2pi ?
The general solution for 2sqrt(3)cos(θ-pi/3)=3,0<= θ<= 2pi is θ= pi/2 ,θ= pi/6