What is the general solution for (sin(115))/(20)=(sin(b))/(11) ?

The general solution for (sin(115))/(20)=(sin(b))/(11) is b=0.52183…+360n,b=180-0.52183…+360n

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(sin(115))/(20)=(sin(b))/(11)

\frac{sin ( 11 5 ^{\circ} )}{20} = \frac{sin ( b )}{11}

b = 0.52183 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.52183 \dots + 36 0^{\circ} n

Solution steps

\frac{sin ( 11 5 ^{\circ} )}{20} = \frac{sin ( b )}{11}

Switch sides

\frac{sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{20}

Multiply both sides by

10

\frac{10 sin ( b )}{11} = \frac{sin ( 11 5 ^{\circ} )}{2}

Multiply both sides by

11

10 sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{2}

Divide both sides by

10

sin (b) = \frac{11 sin ( 11 5 ^{\circ} )}{20}

Apply trig inverse properties

b = arcsin (\frac{11 sin ( 11 5 ^{\circ} )}{20}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{11 sin ( 11 5 ^{\circ} )}{20}) + 36 0^{\circ} n

Show solutions in decimal form

b = 0.52183 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.52183 \dots + 36 0^{\circ} n

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3 cos (\frac{π x}{12}) + 8.4 = 7

sin (x) = \frac{1}{6}, tan (x)

2 sin^{2} (x) + sin (x) - 2 = 0

cos (θ) = \frac{25}{714}

What is the general solution for (sin(115))/(20)=(sin(b))/(11) ?
The general solution for (sin(115))/(20)=(sin(b))/(11) is b=0.52183…+360n,b=180-0.52183…+360n