What is the general solution for (1-2cos(x))(1+sin(x))=0 ?

The general solution for (1-2cos(x))(1+sin(x))=0 is x= pi/3+2pin,x=(5pi)/3+2pin,x=(3pi)/2+2pin

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(1-2cos(x))(1+sin(x))=0

(1 - 2 cos (x)) (1 + sin (x)) = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

(1 - 2 cos (x)) (1 + sin (x)) = 0

Solving each part separately

1 - 2 cos (x) = 0 or 1 + sin (x) = 0

1 - 2 cos (x) = 0 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

1 + sin (x) = 0 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn, x = \frac{3 π}{2} + 2 πn

3 cos (2 x) + 7 sin (x) - 5 = 0

cos^{2} (θ) = \frac{1}{3}

x, sin (\frac{x}{5}) = - \frac{3}{2}

sin (B) = \frac{3}{10}

3 = 23 - 3 cot (x)

What is the general solution for (1-2cos(x))(1+sin(x))=0 ?
The general solution for (1-2cos(x))(1+sin(x))=0 is x= pi/3+2pin,x=(5pi)/3+2pin,x=(3pi)/2+2pin