What is the general solution for -2cos^2(θ)-8cos(θ)-1=-5cos(θ) ?

The general solution for -2cos^2(θ)-8cos(θ)-1=-5cos(θ) is θ=pi+2pin,θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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-2cos^2(θ)-8cos(θ)-1=-5cos(θ)

- 2 cos^{2} (θ) - 8 cos (θ) - 1 = - 5 cos (θ)

θ = π + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

- 2 cos^{2} (θ) - 8 cos (θ) - 1 = - 5 cos (θ)

Solve by substitution

cos (θ) = - 1, cos (θ) = - \frac{1}{2}

cos (θ) = - 1 : θ = π + 2 πn

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Combine all the solutions

θ = π + 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

- 6 sin (θ) = - 33

2 sin (2 x) + cos (x) = 0

sin (d) = 0.81

sec (\frac{5 x}{4}) = 2

t, 16 sin (t) cos (t) = 6 sin (t)

What is the general solution for -2cos^2(θ)-8cos(θ)-1=-5cos(θ) ?
The general solution for -2cos^2(θ)-8cos(θ)-1=-5cos(θ) is θ=pi+2pin,θ=(2pi)/3+2pin,θ=(4pi)/3+2pin