What is the general solution for cos^2(x)-2cos(x)-2=0 ?

The general solution for cos^2(x)-2cos(x)-2=0 is x=2.39212…+2pin,x=-2.39212…+2pin

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cos^2(x)-2cos(x)-2=0

cos^{2} (x) - 2 cos (x) - 2 = 0

x = 2.39212 \dots + 2 πn, x = - 2.39212 \dots + 2 πn

Solution steps

cos^{2} (x) - 2 cos (x) - 2 = 0

Solve by substitution

cos (x) = 1 + 3, cos (x) = 1 - 3

cos (x) = 1 + 3 :

No Solution

cos (x) = 1 - 3 : x = arccos (1 - 3) + 2 πn, x = - arccos (1 - 3) + 2 πn

Combine all the solutions

x = arccos (1 - 3) + 2 πn, x = - arccos (1 - 3) + 2 πn

Show solutions in decimal form

x = 2.39212 \dots + 2 πn, x = - 2.39212 \dots + 2 πn

tan (x) = \frac{14.9}{13.3}

3 sin^{2} (x) + sin (x) - 4 = 0, 0 \leq x \leq 2 π

sin (θ) + 2 = 0

2 tan (2 x) - 10 = 3.4641

8 cos^{2} (x) + 14 cos (x) = - 3

What is the general solution for cos^2(x)-2cos(x)-2=0 ?
The general solution for cos^2(x)-2cos(x)-2=0 is x=2.39212…+2pin,x=-2.39212…+2pin