What is the general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi ?

The general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi is t=-1.17600…+2pi

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tan(t)=-12/5 ,(3pi)/2 <t<2pi

tan (t) = - \frac{12}{5}, \frac{3 π}{2} < t < 2 π

t = - 1.17600 \dots + 2 π

Solution steps

tan (t) = - \frac{12}{5}, \frac{3 π}{2} < t < 2 π

Apply trig inverse properties

t = arctan (- \frac{12}{5}) + πn

Solutions for the range

\frac{3 π}{2} < t < 2 π

t = - arctan (\frac{12}{5}) + 2 π

Show solutions in decimal form

t = - 1.17600 \dots + 2 π

3 sin (x) + 5 cos (x) = 4

- 2 = sec (x)

2 sin^{2} (x) + 4 sin (x) = 2 cos^{2} (x) + 1

y, sec^{2} (y) = x

tan (β) = \frac{1}{3}

What is the general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi ?
The general solution for tan(t)=-12/5 ,(3pi)/2 <t<2pi is t=-1.17600…+2pi