What is the general solution for 0.5=1-sin(θ) ?

The general solution for 0.5=1-sin(θ) is θ= pi/6+2pin,θ=(5pi)/6+2pin

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0.5=1-sin(θ)

0.5 = 1 - sin (θ)

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

0.5 = 1 - sin (θ)

Switch sides

1 - sin (θ) = 0.5

Move

1

to the right side

- sin (θ) = - 0.5

Divide both sides by

- 1

sin (θ) = 0.5

General solutions for

sin (θ) = 0.5

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

θ, r = 6 sin (2 θ)

1.5 sin (3 0^{\circ}) = sin (x)

3 sin (x) - 3 cos (x) = 6

tan (θ) = \frac{11}{100}

sin (x) = \frac{4}{41}

What is the general solution for 0.5=1-sin(θ) ?
The general solution for 0.5=1-sin(θ) is θ= pi/6+2pin,θ=(5pi)/6+2pin