What is the general solution for 1/(sqrt(2))=sin(x) ?

The general solution for 1/(sqrt(2))=sin(x) is x= pi/4+2pin,x=(3pi)/4+2pin

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1/(sqrt(2))=sin(x)

\frac{1}{2} = sin (x)

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

Solution steps

\frac{1}{2} = sin (x)

Switch sides

sin (x) = \frac{1}{2}

Simplify

\frac{1}{2} : \frac{2}{2}

General solutions for

sin (x) = \frac{2}{2}

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (3 x) - sin (x) = - 2 sin (2 x) sin (x)

x, 0.05 cos (x) = - sin (x)

cos (x^{\circ}) = \frac{20.26}{26.4473}

cos (x) = \frac{- \frac{4}{3} 3}{\frac{8}{3} 3}

cos (θ) = \frac{3}{10}

What is the general solution for 1/(sqrt(2))=sin(x) ?
The general solution for 1/(sqrt(2))=sin(x) is x= pi/4+2pin,x=(3pi)/4+2pin