What is the general solution for sin(x-90)=cos(x) ?

The general solution for sin(x-90)=cos(x) is x=90+360n,x=270+360n

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sin(x-90)=cos(x)

sin (x - 9 0^{\circ}) = cos (x)

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (x - 9 0^{\circ}) = cos (x)

Rewrite using trig identities

- cos (x) = cos (x)

Subtract

cos (x)

from both sides

- 2 cos (x) = 0

Divide both sides by

- 2

cos (x) = 0

General solutions for

cos (x) = 0

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

cos (x) = \frac{67}{77}

(sin (x) + cos (x))^{2} = \frac{1 + 2 sin ( x )}{sec ( x )}

cot (\frac{π}{3}) = tan (x)

3 cot (x) + 1 = 2 + 4 cot (x), 0^{\circ} \leq x \leq 36 0^{\circ}

sin (x) = \frac{48.35}{50.14}

What is the general solution for sin(x-90)=cos(x) ?
The general solution for sin(x-90)=cos(x) is x=90+360n,x=270+360n