What is the general solution for sin(3x)=0,0<x<= 2 ?

The general solution for sin(3x)=0,0<x<= 2 is x= pi/3

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sin(3x)=0,0<x<= 2

sin (3 x) = 0, 0 < x \leq 2

x = \frac{π}{3}

Solution steps

sin (3 x) = 0, 0 < x \leq 2

General solutions for

sin (3 x) = 0

3 x = 0 + 2 πn, 3 x = π + 2 πn

Solve

3 x = 0 + 2 πn : x = \frac{2 πn}{3}

Solve

3 x = π + 2 πn : x = \frac{π}{3} + \frac{2 πn}{3}

x = \frac{2 πn}{3}, x = \frac{π}{3} + \frac{2 πn}{3}

Solutions for the range

0 < x \leq 2

x = \frac{π}{3}

tan (x) = - 0.35

0 = cos (2 t - \frac{π}{3})

sin (0.5 x) = 0

cos (2 x) = 2 - 3 sin (x), \frac{π}{2} \leq x \leq \frac{3 π}{2}

3 sin (x) cos (x) = 0

What is the general solution for sin(3x)=0,0<x<= 2 ?
The general solution for sin(3x)=0,0<x<= 2 is x= pi/3