What is the general solution for sin(x)=cos(19) ?

The general solution for sin(x)=cos(19) is x=360n+71,x=180-71+360n

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sin(x)=cos(19)

sin (x) = cos (1 9^{\circ})

x = 36 0^{\circ} n + 7 1^{\circ}, x = 18 0^{\circ} - 7 1^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) = cos (1 9^{\circ})

Rewrite using trig identities

sin (x) = sin (9 0^{\circ} - 1 9^{\circ})

Apply trig inverse properties

x = 9 0^{\circ} - 1 9^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} - (9 0^{\circ} - 1 9^{\circ}) + 36 0^{\circ} n

x = 9 0^{\circ} - 1 9^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 7 1^{\circ}

x = 18 0^{\circ} - (9 0^{\circ} - 1 9^{\circ}) + 36 0^{\circ} n : x = 18 0^{\circ} - 7 1^{\circ} + 36 0^{\circ} n

x = 36 0^{\circ} n + 7 1^{\circ}, x = 18 0^{\circ} - 7 1^{\circ} + 36 0^{\circ} n

\frac{1}{1.5} = \frac{sin ( 3 0 ^{\circ} )}{sin ( x )}, x < 9 0^{\circ}

tan (A) = \frac{8}{15}

tan^{2} (θ) = sec^{2} (θ) + 1

cos (2 B) = \frac{21}{35}, cos (B)

2 cos^{4} (x) + 3 sin^{2} (x) - 2 = 0

What is the general solution for sin(x)=cos(19) ?
The general solution for sin(x)=cos(19) is x=360n+71,x=180-71+360n