What is the general solution for 2sqrt(3)sec(θ)+4=0 ?

The general solution for 2sqrt(3)sec(θ)+4=0 is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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2sqrt(3)sec(θ)+4=0

23 sec (θ) + 4 = 0

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

23 sec (θ) + 4 = 0

Move

4

to the right side

23 sec (θ) = - 4

Divide both sides by

23

sec (θ) = - \frac{2 3}{3}

General solutions for

sec (θ) = - \frac{2 3}{3}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

3 sin (x) = 2

\frac{sin ( 7 4 ^{\circ} )}{8} = \frac{sin ( a )}{4}

sin (x) = sin (x - \frac{π}{2})

tan (x) = \frac{π}{3}

- 7 tan (a) - 14 = tan (a) - 6

What is the general solution for 2sqrt(3)sec(θ)+4=0 ?
The general solution for 2sqrt(3)sec(θ)+4=0 is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin