What is the general solution for cos^2(2x)-3cos(2x)=0 ?

The general solution for cos^2(2x)-3cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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cos^2(2x)-3cos(2x)=0

cos^{2} (2 x) - 3 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

cos^{2} (2 x) - 3 cos (2 x) = 0

Solve by substitution

cos (2 x) = 3, cos (2 x) = 0

cos (2 x) = 3 :

No Solution

cos (2 x) = 0 : x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

csc^{2} (x) = sin (x)

cos (θ) = \frac{4}{7}, tan (θ) < 0

tan (θ) = \frac{4}{2}

e^{s i n (x)} - e^{- s i n (x)} = 2

cos (x) \cdot sec (x) \cdot cot^{2} (x) = csc^{2} (x)

What is the general solution for cos^2(2x)-3cos(2x)=0 ?
The general solution for cos^2(2x)-3cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin