What is the general solution for sqrt(2)sin(x-20)+1=0 ?

The general solution for sqrt(2)sin(x-20)+1=0 is x=360n+245,x=360n+335

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sqrt(2)sin(x-20)+1=0

2 sin (x - 2 0^{\circ}) + 1 = 0

x = 36 0^{\circ} n + 24 5^{\circ}, x = 36 0^{\circ} n + 33 5^{\circ}

Solution steps

2 sin (x - 2 0^{\circ}) + 1 = 0

Move

1

to the right side

2 sin (x - 2 0^{\circ}) = - 1

Divide both sides by

2

sin (x - 2 0^{\circ}) = - \frac{2}{2}

General solutions for

sin (x - 2 0^{\circ}) = - \frac{2}{2}

x - 2 0^{\circ} = 22 5^{\circ} + 36 0^{\circ} n, x - 2 0^{\circ} = 31 5^{\circ} + 36 0^{\circ} n

Solve

x - 2 0^{\circ} = 22 5^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 24 5^{\circ}

Solve

x - 2 0^{\circ} = 31 5^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 33 5^{\circ}

x = 36 0^{\circ} n + 24 5^{\circ}, x = 36 0^{\circ} n + 33 5^{\circ}

9.2 cos (x) = 6.3

sec (x) + 3 tan (x) = 1 + 2 tan (x)

2 sin (3 x) = 0

x, cos (x) - sin (x + y) = 0

sin (x) = - cos (4 x)

What is the general solution for sqrt(2)sin(x-20)+1=0 ?
The general solution for sqrt(2)sin(x-20)+1=0 is x=360n+245,x=360n+335