What is the general solution for -sqrt(2)sin(x)=1 ?

The general solution for -sqrt(2)sin(x)=1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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-sqrt(2)sin(x)=1

- 2 sin (x) = 1

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

- 2 sin (x) = 1

Divide both sides by

- 2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

- 5 sin (x) = - 2 cos^{2} (x) + 4, 0 \leq x \leq 2 π

6 = sin (\frac{π}{4} x) + 5

2 cos (θ) + 1 = 0, 0 \leq θ \leq 2 π

t, 4.6 = 0.106 cos (4.36 t)

sin (x) = \frac{23}{24}

What is the general solution for -sqrt(2)sin(x)=1 ?
The general solution for -sqrt(2)sin(x)=1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin