What is the general solution for solvefor x,1+sin(2x-30)=0 ?

The general solution for solvefor x,1+sin(2x-30)=0 is x=180n+150

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solvefor x,1+sin(2x-30)=0

solve for

x, 1 + sin (2 x - 3 0^{\circ}) = 0

x = 18 0^{\circ} n + 15 0^{\circ}

Solution steps

1 + sin (2 x - 3 0^{\circ}) = 0

Move

1

to the right side

sin (2 x - 3 0^{\circ}) = - 1

General solutions for

sin (2 x - 3 0^{\circ}) = - 1

2 x - 3 0^{\circ} = 27 0^{\circ} + 36 0^{\circ} n

Solve

2 x - 3 0^{\circ} = 27 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 15 0^{\circ}

x = 18 0^{\circ} n + 15 0^{\circ}

cos (x^{2}) = sin (x^{2})

\frac{cos ( - x )}{sin ( x )} = 0

5 sin (2 x) + 3 cos (2 x) = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

cos (θ) = 0.6798, 0^{\circ} \leq θ \leq 36 0^{\circ}

\frac{2 sin ( x ) cos ( x )}{cos ( x )} = 1

What is the general solution for solvefor x,1+sin(2x-30)=0 ?
The general solution for solvefor x,1+sin(2x-30)=0 is x=180n+150